Error in coding Python

Development Python
1

Hi there,

I’m trying to do something extremely simple. I have a list and want to append a variable to it (in the middle of a for loop).

i = “c”
matchlist = [“a”,“b”]
i = str(i)
matchlist = matchlist.append(i)

I expected to get a list ‘matchlist’ with two records (‘a’ and ‘b’) in it and then append a new record ‘c’ to that list. However instead the list loses its type and the value comes up as

Any pointers on where I’m going wrong?

Many thanks.

2

you dont have to do matchlist = matchlist.append(i)

matchlist is an array, so just append the element

reassigning matchlist = matchlist.append(i) will make matchlist as type of the append() operation.

3

to append you need not assign it to the list name again … you can simply right …
matchlist.append(i)

it will work…!

1234
1234.PNG1324×689 6.61 KB

I have checked… you can try like this

4

In your code you don’t need to assign the method into the variable.As in python append is use as a method that will do changes to the list itself on which method is performed.So you just need to write

i=“c”
matchlist = [“a”,“b”]
matchlist.append(i)
print(matchlist)
[“a”, “b”, “c”] #output

i=str(i) , is also not required as the input you are providing is a string

5

you don’t need to assign matchlist to matchlist.append(i)
since matchlist is an array the element can be simply appended.
moreover you may avoid the line
i=str(i)
as it doesn’t bring any change to the code. since i is given the value of a string there is no point in writing this line.

6

you can write code for this problem:

image
image821×888 30.7 KB

7

List=[“a” , “b”]
print(List)
List.append(“c”)
print(List)
List.insert(1, “D”)
print(List)

8

in python after writing list , you need not assign the list name again just use the append() statement for adding the new element in list
here are the code:-
i=“c”
matchlist=[“a”,“b”]
matchlist.append(i)
print(matchlist)

9

In python programming language after writing list , You not need to assign the list name again just use the append() function of list, statement for adding the new element in list
after checking all condition that i have cleared with you then also you face same error then please check my code -

i=“c”
matchlist=[‘a’,‘b’]
matchlist.append(i)
print(matchlist)

10

Check My Code -

L1 = [“a”, “b”]
L1.append(“c”)
print(L1)

11

List=[“a” , “b”]
print(List)
List.append(“c”)
print(List)
List.insert(1, “D”)
print(List)

12

List=[“a” , “b”]
print(List)
List.append(“c”)
print(List)
List.insert(1, “D”)
print(List)

try this code… i feel that the error is with the quotations you are using… your quotes are behaving like a character other than “”

13

Correct code
i = “c”
matchlist = [“a”, “b”]
i = str(i)
matchlist.append(i)
print(matchlist)

14

line no3 is actually not required because you already set i as string c (anything inside a double or single quote is a string). you dont need to assign matchlist.append(i) to matchlist.
CODE:

i = 'c'
matchlist = ['a','b']
matchlist.append(i)
print(matchlist)
15

i = “c”

matchlist = [“a”,“b”]

matchlist.append(i)

print(list)

image
image1180×49 6.9 KB

for append function,instead of using matchlist = matchlist.append(i) ,use list.append(i).

16

In your code the third line(i=str(i)) is not required because you have already set i=‘c’ which represents a string in python.You don’t need to assign matchlist to matchlist.append(i).You can write your code as below:
i=“c”
matchlist=[“a”,“b”]
matchlist.append(i)
print(matchlist)
#Output:[“a”,“b”,“c”]

17

There should not be the append() method is assigned to the same array or list.
You can simply use " matchlist.append(i) " rather than assigning it to the matchlist variable.