Please help me. I’m nit receiving telegram msg. Error is occurring. Tried so much. Creat new bot account also. Still not rectified.
Hi @sanketbagde38
In your conf.py file
Telegram_Chat_id should be the only @temp_alert_read, not @temp_alert_read_bot. Check this and try.
Let me know it helped or not.
Hi @sanketbagde38
Check your code with this, and let me know.
import requests # for making HTTP requests
import json # library for handling JSON data
import time # module for sleep operation
from boltiot import Bolt # importing Bolt from boltiot module
import conf # config file
mybolt = Bolt(conf.bolt_api_key, conf.device_id)
def get_sensor_value_from_pin(pin):
"""Returns the sensor value. Returns -999 if request fails"""
try:
response = mybolt.analogRead(pin)
data = json.loads(response)
if data["success"] != 1:
print("Request not successfull")
print("This is the response->", data)
return -999
sensor_value = int(data["value"])
return sensor_value
except Exception as e:
print("Something went wrong when returning the sensor value")
print(e)
return -999
def send_telegram_message(message):
"""Sends message via Telegram"""
url = "https://api.telegram.org/" + conf.telegram_bot_id + "/sendMessage"
data = {
"chat_id": conf.telegram_chat_id,
"text": message
}
try:
response = requests.request(
"POST",
url,
params=data
)
print("This is the Telegram URL")
print(url)
print("This is the Telegram response")
print(response.text)
telegram_data = json.loads(response.text)
return telegram_data["ok"]
except Exception as e:
print("An error occurred in sending the alert message via Telegram")
print(e)
return False
while True:
# Step 1
sensor_value = get_sensor_value_from_pin("A0")
print("The current sensor value is:", sensor_value)
# Step 2
if sensor_value == -999:
print("Request was unsuccessfull. Skipping.")
time.sleep(10)
continue
# Step 3
if sensor_value >= conf.threshold:
print("Sensor value has exceeded threshold")
message = "Alert! Sensor value has exceeded " + str(conf.threshold) + \
". The current value is " + str(sensor_value)
telegram_status = send_telegram_message(message)
print("This is the Telegram status:", telegram_status)
# Step 4
time.sleep(10)
1 Like
This error is occure because of telegram chat id remove “@temp_alert_read_bot” instead of type only
“@temp_alert_read” and rerun code i think that is the same chat id you will find in the information of your telegram channel.
Hi @sanketbagde38 ,
I think you are entering the bot username inside chat id that is incorrect. Also, can you show me the permanent link as you can see in my screenshot. You can get it by clicking on the channel name.
@rahul.singh1
Sir i didnt get the page may be in ios while creating the channel, that page was shown. but i get the permanent link
https://t.me/temp_alert_read_bot
Hi @aniketzepale4,
Text after t.me is your chat id.
For example:
t.me/temp_reading
then you chat id would be
telegram_chat_id = "@temp_reading"
Also admin should be member of this channel.
Do let me know in case you need further assistance.
Thank you everyone 
@rahul.singh1 @phaniraghavendra661 @aniketzepale4
I got my output
Assuming that ios telegram is not allowing.
I make an account in android. And it work’s.
1 Like
“”“Configurations for telegram_alert.py”""
bolt_api_key = “XXXX”
device_id = “BOLTXXXX”
telegram_chat_id = “@temp_alert_read” # Try this as your chat id
telegram_bot_id = “botXXXX”
threshold = 250
Your telegram_chat_id has an extra word bot. Try using the code explained above.